The purpose of this lab is to acquaint you with the use of double and triple integrals to determine centers of mass and centroids of regions in three dimensions.
In designing mechanisms or structures, one often has to deal with distributed forces, that is, forces that do not act at a discrete, finite set of points. The most common example of a distributed force is the force of gravity, which acts on all parts of any body of matter. Other examples are pressure in fluids and electrostatic forces, though there are many others.
One of the basic useful principles of analyzing distributed forces is
the idea of replacing them with a single, aggregate force
that acts at a single point and is somehow equivalent to the original
distributed force. This may not always be possible, but this technique
has found great use in engineering and science. As a simple example,
suppose we have a solid plate of uniform thickness and density, but
irregular shape. Finding the equivalent force is really the problem of
finding the point where we could exactly balance the plate. This
balance point is often called the center of mass of the body.
For symmetric objects, the balance point is usually easy to find. For example, the balance point of a see-saw is the exact center. Similarly, the balance points for rectangles or circles are the just the geometrical centers. For non-symmetric objects, the answer is not so clear, but it turns out that there is a fairly simple algorithm involving integrals for determining balance points.
To describe the algorithm abstractly, suppose that we have a
three-dimensional body occupying a region D in 3. Suppose
further, that the density of the body is described by a function
defined on D. Then the mass m of our body can be
computed by the triple integral

and the coordinates, written
, of the
center of mass can be shown to be given by the three equations

As an example, consider the unit cube, and suppose, for the sake of
simplicity, that
is constant and equal to 1. Then the mass is also
unity and
are given by

Performing the three integrals gives
, as expected from symmetry.
are independent of
and are given by

where V is the volume of the domain D.
In this case, the point
is called the centroid of the domain D.
, and on the right by the
vertical line x=a, where k and a are positive constants. Note
that your answer will depend on the parameters k and b.
and the x-y
plane.
,
, the x-y plane, and
if
is given by
