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- 1.
- Consider the function on the interval [0,2]. Very soon you will be able to use calculus to determine that the area under this curve is exactly equal to . For each of the left endpoint, right endpoint, and midpoint rules, determine the minimum number of subintervals required to approximate the area to within 0.01. Which method works best?
- 2.
- Now consider the function on the
interval [0,2]. Repeat the procedure for the previous exercise,
using only the midpoint rule. That is, find the minimum number of
subintervals required to approximate the area to within 0.01. (The
exact value of the area in this case is 643/60 -
*cos*(40)/20.) Explain why more subintervals are needed for this function than were required for the function in the first exercise. You might find the error bound formula helpful. - 3.
- Consider the function
*g*(*x*) = -*x*-2^{4}*x*+3^{3}*x*on the interval [-3,1].^{2}- (a)
- If
*M*is used to approximate the area under the curve, what accuracy is guaranteed by the error bound formula? Make sure you state clearly how you obtained the value of_{30}*B*. - (b)
- Use the error bound formula to find the smallest value of
*n*that guarantees that*M*_{n}approximates the area to within 0.00001. That is, find the smallest value of*n*that guarantees that .

- 4.
- Consider the area under the curve on the
interval [-2,2].
- (a)
- Use the formula for the area of a circle to compute the exact value of this area.
- (b)
- Using the left endpoint rule, find the minimum number of
subintervals required to approximate this area to within a tolerance
of 0.05. That is find the value of
*n*such that , but . - (c)
- Repeat the previous part of this exercise using the midpoint rule.
- (d)
- Explain why the error bound formula cannot be used for this function on this interval.

11/2/1999