MA2051 - Ordinary Differential Equations
Sample Exam 2 Solutions - A96
Second Exam - Originally Given 1993 A Term
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1
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A
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dynes/cm; the model is 200 x''
+ 24,500 x = 0, x(0) = 0, x'(0) = -6.
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B
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Use characteristic equations: ; . Hence, a general solution is . The initial conditions force ,
C2 = -.06/11.07 = -.00542 . Hence, .
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C
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To find the period, solve to find s.
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D
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The maximum displacement occurs in when the sine function is . Hence, the maximum
displacement (or amplitude of the motion) is 1.85 cm.
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2
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A
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Use undetermined coefficients. First guess . Because these functions are solutions of the
homogeneous equation, the correct guess is . Substitute and collect coefficients of sine and
cosine to find A = 0, B = 1/4. Hence, .
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B
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Using the particular solution just found and the
given homogeneous solutions, .
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C
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Because of the leading factor of t in ,
the solution grows without bound. The system is being forced at
its resonant frequency.
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3
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A
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r = -4, 2
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B
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.
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C
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Choose , .
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4
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A
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Write .
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B
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C
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Let . Then
and
- . Using partial fractions, we find
Then , , and
Hence, the solution is
© 1996 by Will Brother.
All rights Reserved. File last modified on December 6, 1996.