The characteristic equation is
The roots are complex, .
and
The Wronskian is given by the determinant
After simplification, and using the trig identity , we get
and the derivative is
So plugging in t=0 gives the two equations
Solving gives ,
.
The general solution to the homogeneous equation is
This gives
so
Comparing to the forcing term, we get A=1, B=0, so
The general solution is
The derivative is
so the equations to be satisfied are
The characteristic equation is
So the roots are r=-1 and r=-3.
For r=-3, the equation is A + B =0 so a good choice is A=1, B=-1. For r=-1, the equation is -A + B =0 so a good choice is A=1, B=1. So the two linearly independent solutions are
and
The equations to be satsified are
so and
. The solution is