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The purpose of this lab is to find solutions to one equation.
You can set an expression or function equal to another expression, function, or number inside a solve command.As an example, you may want to find where the following two parabolas intersect.
> g := 9*x^214;
> h:=x^2;
> plot([g,h],x=2..2);
> solve(g=h,x);
The plot shows that there are two intersection points and the solve command finds both values.It is good to get into the habit of naming your output so you can use it in a later command. Giving the values a name makes it easy to plug them into the function to find the values.
> ip:=solve(g=h,x);
Since there are two values called , use [ ] to call up the one you want.
> eval(g,x=ip[1]);
> eval(h,x=ip[2]);
Therefore the two intersection points are
and
. This seems like the answer shown on the graph.
If you would like to find where the following function crosses the horizontal line you can try the solve command.
> j:=x>2*x^315*x^22*x+5;
> k:=x>50;
> plot([j(x),k(x)],x=3..8);
The graph shows there should be three answers.
> solve(j(x)=k(x),x);
That is some scary output! So instead of using the algebraic solve try the numerical fsolve.
> fsolve(j(x)=k(x),x);
If you want to find where the following function crosses the xaxis, just set it equal to zero.
> f:=theta>1/2*theta+sin(theta);
> plot(f(theta),theta=8*Pi..8*Pi);
> solve(f(theta)=0,theta);
Wow, what is that?!?! We know from the graph that there should be three answers and solve wasn't a great option so try fsolve again.
> fsolve(f(theta)=0,theta);
Where are the other two answers!? This is actually how fsolve usually works. It shoots for one answer and only gives that one. But you can tell fsolve where to look by getting an idea from the graph and typing that domain into the fsolve command.
> a:=fsolve(f(theta)=0,theta=5..1);
> b:=fsolve(f(theta)=0,theta=1..1);
> c:=fsolve(f(theta)=0,theta=1..5);
To find the values just plug in the names of the values.
> f(a);
> f(b);
> f(c);
(Of course the yvalues are zero!)
If is explicitly defined as a function of and , you can use function notation and generate a surface plot using Maple's plot3d command. If is not explicitly solved for and assumed to be a function of and , the implicit equation can be defined as an expression and you can generate a surface plot using Maple's implicitplot3d command. A few examples are shown below.
> f:=(x,y)>x^2+y^2;
> plot3d(f(x,y),x=5..5,y=5..5);
> f(2,1);
> surf:=x^2+y^2+z^2=9;
> with(plots):
> implicitplot3d(surf,x=5..5,y=5..5,z=5..5);
> solve(eval(surf,{x=2,y=1}),z);
 Given the expression
,
 A)
 Plot the expression and in text state how many roots it has. That is, how many times the it crosses the xaxis.(Experiment with domain values until you find values that show the crossing points clearly.)
 B)
 Compare outputs from the Maple solve and fsolve command to find the values of where it crosses the xaxis. State the real roots in text.
 C)
 Use the Maple eval command to evaluate the expression at each of the roots to show that they are zero.
 Given the functions
and
 A)
 Plot the functions. Again experiment with domain values until the intersection points are clear. Then state in text how many intersection points you see.
 B)
 Compare outputs from the Maple solve and fsolve command find the intersection points. Label the values with a variable in front of the solve or fsolve command.
 C)
 Find all corresponding values and state the intersection points in text.(When writing your text sentence use 3 significant figures for the answer. Be sure to round properly!)
 Plot each of the 3D surfaces given below using 5 to 5 for all plotting ranges and find the corresponding value at the point .
 A)

 B)

Next: About this document ...
Up: lab_template
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Dina J. SolitroRassias
20150907